2048-8.2-44A AID: 897 There argon no restrictions as to whether the bar ons retain to be distinguishable flavors. a) For freshman outgo we drive 31 alternatives and for the second absorb again we pay back 31 alternatives therefore by multiplication Principle (Suppose n superiors must(prenominal) be do, with [pic] shipway to bemuse choice 1, and for each of these ship canal, [pic]ways to move over choice 2, and so on with [pic] ways to actualize choice n. because [pic] different ways to thread the entire order of choices) the spotlight of different double-scoop cones result be [pic]= [pic] b) For first scoop we have 31 choices, for the second scoop we have 31 choices and for third scoop again we have 31 choices thus by propagation Principle (Suppose n choices must be make, with [pic] ways to shape choice 1, and for each of these ways, [pic]ways to sack up choice 2, and so on with [pic] ways to make choice n. Then [pic] different ways to make the entire sequence of choices) the issuance of different triple-scoop cones pull up stakes be [pic]= [pic] = [pic] c) Here order does non matter, so use gangs. The fall of combinations of n elements taken r at time, where [pic] is given by [pic]and [pic]= [pic].
Therefore the number of combination choosing 2 scoop fall out of 31 flavors are [pic]= [pic] = [pic]{As [pic] = [pic]} = [pic] = [pic] accordingly there are 465 eHways to make double-scoop cones with two different flavors. In addition, there would be 31 ways to make double-scoop cones with the akin flavors. Therefore, [pic]= [pic] double-scoop cones can be made if order doesnt matter.If you compliments to get a surface essay, order it on our website:
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